3(3x^2-4/3)=0

Solution for 3(3x^2-4/3)=0 equation:

3(3x^2-4/3)=0

We multiply parentheses

9x^2-4/3*3=0

We multiply all the terms by the denominator


9x^2*3*3-4=0

Wy multiply elements

81x^2*3-4=0

Wy multiply elements

243x^2-4=0

a = 243; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·243·(-4)
Δ = 3888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3888}=\sqrt{1296*3}=\sqrt{1296}*\sqrt{3}=36\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{3}}{2*243}=\frac{0-36\sqrt{3}}{486}
=-\frac{36\sqrt{3}}{486}
=-\frac{2\sqrt{3}}{27}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{3}}{2*243}=\frac{0+36\sqrt{3}}{486}
=\frac{36\sqrt{3}}{486}
=\frac{2\sqrt{3}}{27}
$